Ln(5x-4)^1/3=1

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Solution for Ln(5x-4)^1/3=1 equation: 


D( x )

5*x-4 <= 0

5*x-4 <= 0

5*x-4 <= 0

5*x-4 <= 0 // + 4

5*x <= 4 // : 5

x <= 4/5

x in (4/5:+oo)

((ln(5*x-4))^1)/3 = 1 // - 1

((ln(5*x-4))^1)/3-1 = 0

ln(5*x-4)/3-1 = 0

1/3*ln(5*x-4)-1 = 0 // + 1

1/3*ln(5*x-4) = 1 // : 1/3

ln(5*x-4) = 1/1/3

ln(5*x-4) = 3

ln(5*x-4) = ln(e^3)

5*x-4 = e^3

5*x-e^3-4 = 0 // + e^3+4

5*x = e^3+4 // : 5

x = (e^3+4)/5

x = (e^3+4)/5

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